Ile gram wodorotlenku sodu potrzeba do zobojętnienia 12 gram kwasu fosforowego?
3NaOH + H3PO4 -> Na3PO4 + 3H2O3 mol NaOH -- 1 mol H3PO4x -- 12g H3PO4x = 36g
3NaOH + H3PO4 -> Na3PO4 + 3H2O
mNaoh=23+1+16=40g
mH3Po4=3+31+4*16=98g
3*40g - 98g
xg -12g
98x=1440
x=1440/98=≈14,69
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3NaOH + H3PO4 -> Na3PO4 + 3H2O
3 mol NaOH -- 1 mol H3PO4
x -- 12g H3PO4
x = 36g
3NaOH + H3PO4 -> Na3PO4 + 3H2O
mNaoh=23+1+16=40g
mH3Po4=3+31+4*16=98g
3*40g - 98g
xg -12g
98x=1440
x=1440/98=≈14,69