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Verified answer
C₁ = 3 μFC₂ = 7 μF
Cs = (C₁•C₂) / (C₁ + C₂)
Cs = (3 • 7) / (3 + 7)
Cs = 21 / 10 μF
V = 12 + 13
V = 25 kV
V = 25 • 10³ V
Q = Cs • V
Q = 21 / 10 • 25 • 10³
Q = 52500 μC
Q = 5,25 x 10⁻² C
Q = Q₁ (seri)
V₁ = Q₁ / C₁
= 5,25 x 10⁻² / 3 x 10⁻⁶
= 1,75 x 10⁴ V
= 17,5 kV
A