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I₁=12 mA=12.10⁻³ A
I₂=6 mA=6.10⁻³A
V₁=3 Volt
V₂=6 Volt
Ditanyakan: ΔR=...Ω
Dijawab:
Pakai hukum Ohm
V=IR
R₁=V₁/I₁
=3/12.10⁻³
=10³/4
=2,5.10² Ω
=250Ω
R₂=V₂/I₂
=6/6.10⁻³
=10³
=1000 Ω
maka besar hambatannya:
ΔR=R₂-R₁
=1000-250
=750 Ohm
∵Selesai