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Vo = V0x = 4 Km / h
x = 4 Km
h =?
SOLUCIÓN :
Transformaciones :
4 Km /h * 1000 m/ 1 Km* 1h/3600 seg = 1.11 m/seg
4 Km * 1000 m/ 1 Km= 4000 m
Para resolver el ejercicio se aplican las formulas de lanzamiento
horizontal :
x = Vox * tv
tv = x / Vox = 4000m / 1.11 m/seg
tv = 3603.60 seg
Altura a la que se encontraba :
h = g * tv²/2
h= 9.8 m/seg² * ( 3603.60 seg)²/2
h= 63631071.5 m * 1km / 1000 m = 63631.07 Km .