Respuesta:
el AB es area de la base, y espero q te ayude si :3
Explicación paso a paso:
del prima:
V = AB * h
AB = [tex]\sqrt{34.1*(34.1-10)(34.1-10)(34.1-14.4)} \\\sqrt{34.1*24.1*24.1*20} =>629.3[/tex]
entonces = 629.3 * 12 = 7552.5[tex]cm^{3}[/tex]
del cilindro
AB = π*[tex]r^{2}[/tex] (r=4)
AB = 3.14 * [tex]4^{2}[/tex] => 50.24
entonces: 50.24 * 12 = 602.88 [tex]cm^{3}[/tex]
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Respuesta:
el AB es area de la base, y espero q te ayude si :3
Explicación paso a paso:
del prima:
V = AB * h
AB = [tex]\sqrt{34.1*(34.1-10)(34.1-10)(34.1-14.4)} \\\sqrt{34.1*24.1*24.1*20} =>629.3[/tex]
entonces = 629.3 * 12 = 7552.5[tex]cm^{3}[/tex]
del cilindro
V = AB * h
AB = π*[tex]r^{2}[/tex] (r=4)
AB = 3.14 * [tex]4^{2}[/tex] => 50.24
entonces: 50.24 * 12 = 602.88 [tex]cm^{3}[/tex]