Samochód jedzie z szybkoscia 72km/h.Oblicz z jaka czestotliwoscia poruszaja sie kola samochodu jezeli ich srednica wynosi 50 cm
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V = 72 km/h = 72*1000 m/3600 s = 20 m/s
2r = 50 cm
r = 25 cm = 0,25 m
f = ?
V = 2πr / T ; ale T = 1/f
V = 2πrf
f = V /2πr
f = 20 m/s / 2 *3,14 *0,25 m
f = 20 m/s /1,57 m
f ≈ 12,8 1/s ≈ 12,8 Hz