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[H⁺] = 10⁻¹
pH akhir = 2
[H⁺] = 10⁻²
volume akhir = 500 ml
V₁ M₁ = V₂ M₂
V₁ x 10⁻¹ = 500 x 10⁻²
V₁ = 50 ml