Hitunglah ph masing masing larutan di bawak ini
a.Ba(OH)2 o,o1M
a.Ba(OH)2 o,o1M
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![M=10^{-2}~M \\ \\ ~[OH^-]=b.M \\ \\ =2.10^{-2} \\ \\ \\ pOH=-log[OH^-] \\ \\ =-log2.10^{-2} \\ \\ =2-log2 \\ \\ \\ pH=14-pOH \\ \\ =14-(2-log2) \\ \\ =12+log2](https://tex.z-dn.net/?f=M%3D10%5E%7B-2%7D%7EM+%5C%5C++%5C%5C+%7E%5BOH%5E-%5D%3Db.M+%5C%5C++%5C%5C+%3D2.10%5E%7B-2%7D+%5C%5C++%5C%5C++%5C%5C+pOH%3D-log%5BOH%5E-%5D+%5C%5C++%5C%5C+%3D-log2.10%5E%7B-2%7D+%5C%5C++%5C%5C+%3D2-log2+%5C%5C++%5C%5C++%5C%5C+pH%3D14-pOH+%5C%5C++%5C%5C+%3D14-%282-log2%29+%5C%5C++%5C%5C+%3D12%2Blog2 "M=10^{-2}~M \\ \\ ~[OH^-]=b.M \\ \\ =2.10^{-2} \\ \\ \\ pOH=-log[OH^-] \\ \\ =-log2.10^{-2} \\ \\ =2-log2 \\ \\ \\ pH=14-pOH \\ \\ =14-(2-log2) \\ \\ =12+log2")
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