n ch3cooh = 150 x 0,1 = 15
n naoh = 100 x 0,1 = 10
M= 15 10 - - (PENYANGGA
B= -10 -10 10 ASAM)
S=5 0 10
pH = Ka x asam lemah/anion asam
= 10^-5 x 5/10
= 0,5 x 10^-5
= 5 x 10^-6
= - log 5.10^-6
= 6 - log 5
Insya allah benar
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n ch3cooh = 150 x 0,1 = 15
n naoh = 100 x 0,1 = 10
M= 15 10 - - (PENYANGGA
B= -10 -10 10 ASAM)
S=5 0 10
pH = Ka x asam lemah/anion asam
= 10^-5 x 5/10
= 0,5 x 10^-5
= 5 x 10^-6
= - log 5.10^-6
= 6 - log 5
Insya allah benar