Diketahui :
panjang AD = 8 cm dan AC = 20
Ditanyakan :
panjang AB, BC dan BD
Jawab :
panjang BD
BD² = AD . DC
BD² = 8 . 12
BD² = 96
BD = √96 = 9√15
panjang AB
AB² = BD² + AD²
AB² = (9√15)² + 8²
AB² = 96 + 64
AB² = 160
AB = √160 = 12√16
panjang BC
BC² = AC² - AB²
BC² = 20² - (12√16)²
BC² = 400 - (144+16)
BC² = 240
BC = √240 = 15√15
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Diketahui :
panjang AD = 8 cm dan AC = 20
Ditanyakan :
panjang AB, BC dan BD
Jawab :
panjang BD
BD² = AD . DC
BD² = 8 . 12
BD² = 96
BD = √96 = 9√15
panjang AB
AB² = BD² + AD²
AB² = (9√15)² + 8²
AB² = 96 + 64
AB² = 160
AB = √160 = 12√16
panjang BC
BC² = AC² - AB²
BC² = 20² - (12√16)²
BC² = 400 - (144+16)
BC² = 240
BC = √240 = 15√15