Hitunglah operasi bentuk akar berikut dengan terlebih dahulu menyerderhanakan bentuk akarnya . a. √2+√32 = b. √6+√54-√250 = c. √32-√2+√8 = d. 4√3-(√27+√12) =
rastogi
A. √2+√32= √2+√16x2= √2+4√2= 5√2 b. √6+√54-√250= √6+√9x6-√25x10= √6+3√6-5√10= 4√6-5√10 c. √32-√2+√8= √16x2-√2+√4x2= 4√2-√2+2√2= 5√2 d. 4√3-(√27+√12)= 4√3-(√9x3+√4x3)= 4√3-(3√3+2√3)= 4√3-√3=3√3
b. √6+√54-√250= √6+√9x6-√25x10= √6+3√6-5√10= 4√6-5√10
c. √32-√2+√8= √16x2-√2+√4x2= 4√2-√2+2√2= 5√2
d. 4√3-(√27+√12)= 4√3-(√9x3+√4x3)= 4√3-(3√3+2√3)= 4√3-√3=3√3
b. √6+√54-√250 =√6 + √9 x 6 + √25x10 = (3+1)√6 + 5√10 = 4√6 + 5 √10
c. √32-√2+√8 =√16x2 -√2 +√4x2 = 4√12-√2+2√2 = (4-1+2)√2 =5√2
d. 4√3-(√27+√12) =4√3 -(√3x9 + √4x3) = 4√3 - (3√3 + 2√3) = 4-5√3= -√3