SalsaMaulida5417
A. Diket = V = 24 cm³, p = 4 cm, l = 3 cm t = V : p x l = 24 cm³ : 4 cm x 3 cm = 2 cm luas seluruh permukaan balok = (p x l x 2) + (p x t x 2) + (l x t x 2) = (4 cm x 3 cm x 2) + (4 cm x 2 cm x 2) + (3 cm x 2 cm x 2) = 24 cm² + 16 cm² + 12 cm² = 52 cm²
b. Diket = V = 315 cm³, p = 9 cm, l = 7 cm t = V : p x l = 315 cm³ : 9 cm x 7 cm = 5 cm luas seluruh permukaan balok = (p x l x 2) + (p x t x 2) + (l x t x 2) = (9 cm x 7 cm x 2) + (9 cm x 5 cm x 2) + (7 cm x 5 cm x 2) = 126 cm² + 90 cm² + 70 cm² = 286 cm²
= 4.3.t = 24
t = 2
LP = 4x3x2 = 24
= 3x2x2 = 12
= 4x2x2 = 16
LP = 52
b. V = plt
= 9.7. t = 315
t = 5
LP = 9x7x2 = 126
= 5x7x2 = 70
= 9x5x2 = 90
= 286
V = 24 cm³, p = 4 cm, l = 3 cm
t = V : p x l
= 24 cm³ : 4 cm x 3 cm
= 2 cm
luas seluruh permukaan balok = (p x l x 2) + (p x t x 2) + (l x t x 2)
= (4 cm x 3 cm x 2) + (4 cm x 2 cm x 2) + (3 cm x 2 cm x 2)
= 24 cm² + 16 cm² + 12 cm²
= 52 cm²
b. Diket =
V = 315 cm³, p = 9 cm, l = 7 cm
t = V : p x l
= 315 cm³ : 9 cm x 7 cm
= 5 cm
luas seluruh permukaan balok = (p x l x 2) + (p x t x 2) + (l x t x 2)
= (9 cm x 7 cm x 2) + (9 cm x 5 cm x 2) + (7 cm x 5 cm x 2)
= 126 cm² + 90 cm² + 70 cm²
= 286 cm²