Jawab:
integral Tertentu
Luas daerah
Penjelasan dengan langkah-langkah:
luas daerah y = x - 2 , x = - 2 , x = 5
i) titk potong y = x - 2 dgn sumbu x, y= 0
x -2= 0
x = 2
ii) luas daerah dari x = -2 sd x = 5
L = L1 + L2
L = - ( ₋₂²∫ (x- 2) dx + ₂⁵∫ ( x- 2) dx
L = - [ 1/2 x² -2x ]²₋₂ + [ 1/2 x² - 2x]⁵₂
L = - [ 1/2 (2²-(-2)² - 2 (2 -(-2)] + [ 1/2 (5² -(2)²) - 2(5 - 2) ]
L = - [ 0 - 2 (4) ] + 1/2 [25-4) - 2 (3)
L = - (-8) + 1/2 (21) - 6
L = 8 + 10,5 - 6
L = 12,5
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Jawab:
integral Tertentu
Luas daerah
Penjelasan dengan langkah-langkah:
luas daerah y = x - 2 , x = - 2 , x = 5
i) titk potong y = x - 2 dgn sumbu x, y= 0
x -2= 0
x = 2
ii) luas daerah dari x = -2 sd x = 5
L = L1 + L2
L = - ( ₋₂²∫ (x- 2) dx + ₂⁵∫ ( x- 2) dx
L = - [ 1/2 x² -2x ]²₋₂ + [ 1/2 x² - 2x]⁵₂
L = - [ 1/2 (2²-(-2)² - 2 (2 -(-2)] + [ 1/2 (5² -(2)²) - 2(5 - 2) ]
L = - [ 0 - 2 (4) ] + 1/2 [25-4) - 2 (3)
L = - (-8) + 1/2 (21) - 6
L = 8 + 10,5 - 6
L = 12,5