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pH = 11 + log 4
pOH = 3 - log 4
[OH⁻] = 4 x 10⁻³
Reaksi ionisasi Fe(OH)₃ :
Fe(OH)₃ ⇆ Fe³⁺ + 3OH⁻
S S 3S
Ksp = [Fe³⁺] [OH⁻]³
4 x 10⁻¹³ = [S] [4 x 10⁻³]³
4 x 10⁻¹³ = 6,4 x 10⁻⁸ x S
S = 4 x 10⁻¹³ / 6,4 x 10⁻⁸
S = 6,25 x 10⁻⁶
Jadi, kelarutannya adalah 6,25 x 10⁻⁶