Question

Hitunglah delta P larutan 9,5 gram gula yang dilarutkan kedalam 90 gram air, tekanan uap air 23,76 mmHg

Answer 1

Dik :
gr terlarut = 9,5 gram
gr pelarut = 90 gram
Mr terlarut = 342
Mr terlarut = 18
P^o = 23,76 mmHg
Dit : delta P = ...?
Jawab :
delta P = P^o.Xt ---> Xt = (gr terlarut/Mr terlarut) / [(gr terlarut/Mr terlarut) + (gr pelarut/Mrpelarut)]
delta P = 23,76.(9,5/342) / [(9,5/342) + (90/18)]
= (23,76 . 0,03) / (0,03 + 5)
= 0,7128 / 5,03 = 0,1417 mmHg