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Q2 = 0,6 C
r = 10 cm = 0,1 m
ditanya : F
F = k .
= 9 x .
= 9 x .
= 9 x x 12
= 108 x N
= 1,08 x N
Q1 = 0,2 C
Q2 = 0,6C
r =10 cm = 0,1 m
dit F...??
jawab:
F = (k . Q1. Q2)/ r^2
F = ( 9 x 10^9 x 0,2C x 0,6C)/ (0,1)^2
F = 108 x 10^9