Jawab:
volume benda putar yang dibatasi oleh kurva y = 3x+2, x = 1 dan x = 3 diputar mengelilingi sumbu x !
V= π ₐᵇ∫ y² dxy = 3x+ 2a = 1b = 3
V = π ₁³∫ (3x+ 2)² dxV = π ₁³∫ (9x² + 12x + 4) dxV = π ( 3x³ + 6x² + 4x)₁³V = π { 3(3³- 1³) + 6(3²- 1²) + 4(3- 1) }V = π { 3(26) + 6(8) + 4(2)}V = π ( 78 + 48 + 8 )V = 134π
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Jawab:
volume benda putar yang dibatasi oleh kurva y = 3x+2, x = 1 dan x = 3 diputar mengelilingi sumbu x !
V= π ₐᵇ∫ y² dx
y = 3x+ 2
a = 1
b = 3
V = π ₁³∫ (3x+ 2)² dx
V = π ₁³∫ (9x² + 12x + 4) dx
V = π ( 3x³ + 6x² + 4x)₁³
V = π { 3(3³- 1³) + 6(3²- 1²) + 4(3- 1) }
V = π { 3(26) + 6(8) + 4(2)}
V = π ( 78 + 48 + 8 )
V = 134π