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b=1
M = 1 mol / 2 Liter = 1/2 Molar atau 0.5 Molar
cara 1 menggunakan 1/2 molar :
[H+] = b x M
[H+] = 1 x 1/2
[H+] = 1/2 molar
pH = -log (1/2)
pH = -log 1 - (-log 2)
pH = log 2
cara 2 menggunakan 0.5 molar :
[H+] = b x Mb
[H+] = 1 x 0.5
[H+] = 0.5 molar
pH = -log 0.5
pH = -log (5x10-¹)
pH = 1 - log 5
selesai. jawabannya adalah log 2 atau 1 - log 5. sama saja. hasilnya.