mol glukosa = 2 mol massa glukosa = mol x Mr = 2 x 180 = 360 gram massa air = 1 kg = 1000 gram massa larutan = massa air + massa glukosa = 1000 + 360 = 1360 gram
% massa glukosa = (massa glukosa / massa larutan) x 100% % massa glukosa = (360 / 1360) x 100% % massa glukosa = 26,47%
2 molal = 2 mol glukosa / 1 kg air
mol glukosa = 2 mol
massa glukosa = mol x Mr = 2 x 180 = 360 gram
massa air = 1 kg = 1000 gram
massa larutan = massa air + massa glukosa = 1000 + 360 = 1360 gram
% massa glukosa = (massa glukosa / massa larutan) x 100%
% massa glukosa = (360 / 1360) x 100%
% massa glukosa = 26,47%