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dan ingat bentuk |x| < a ⇔ -a < x < a
-1 < log(x-1) < 1
sehingga -1 < log(x-1) dan log(x-1) < 1
maka , untuk -1 < log(x-1) ⇒ x -1 > 1/10 ⇒ x > 11/10
untuk log (x-1) < 1 ⇒ x-1 < 10 ⇒ 1 < x < 11
∴ Jadi, Hp = {x| 1.1 < x < 11 , x ∈ R}