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mk=20 g=0,02 kg
vk=600 m/s
Ek=½*m*v²
Ekk=½*0,02*600²=3600 J
rowerzysta:
mr=85 kg
vr=30 km/h= 30*1000m/3600s=8,3 m/s
Ekr=½*85*8,3²=2951,39 J
Ekk/Ekr=3600/2951,39=1,22
Odp: Energia kinetyczna kuli jest 1,22 razy wieksza od energii kinetycznej rowerzysty.