Odpowiedź:
[tex]P_1 = \frac{8^2*\sqrt{3} }{4} = 16\sqrt{3}[/tex]
16[tex]\sqrt{3} cm^2[/tex] Tak
----------------------
[tex]h_2^2 = 8^2 - 6^2 = 64 - 36 = 28 = 4*7[/tex]
[tex]h_2 = 2\sqrt{7}\\h_2 = 2\sqrt{7}[/tex] cm Tak
--------------------------------
Pb = 2*16√3 cm² + 2*0,5*12*2√7 cm² = ( 32√3 + 24 √7 ) cm²
Tak
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Szczegółowe wyjaśnienie:
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Odpowiedź:
[tex]P_1 = \frac{8^2*\sqrt{3} }{4} = 16\sqrt{3}[/tex]
16[tex]\sqrt{3} cm^2[/tex] Tak
----------------------
[tex]h_2^2 = 8^2 - 6^2 = 64 - 36 = 28 = 4*7[/tex]
[tex]h_2 = 2\sqrt{7}\\h_2 = 2\sqrt{7}[/tex] cm Tak
--------------------------------
Pb = 2*16√3 cm² + 2*0,5*12*2√7 cm² = ( 32√3 + 24 √7 ) cm²
Tak
-------
Szczegółowe wyjaśnienie: