Question

Hej!!!Potrzebuje pomocy z zadaniem!

Zadanie 3 z pliku

Answer 1

tgα=⅘

a=4

b=5

c=√4²+5²=√16+25=√41

 

sinα=4√41/41

cosα=5√41/41

 

3sinα=3×4√41/41=12√41/41

4cosα=4×5√41/41=20√41/41

2sinα=2×4√41/41=8√41/41

 

3sinα-4cosα=12√41/41-20√41/41= -8√41/41

 

]3sinα-4cosα]/2sinα=-8√41/41:8√41/41=-1