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JAWAB
⇨ [(2x - 2)/(x²+4x+3)] - (4/(x+3))
⇨ [(2x-2)(x+3) - 4(x²+4x+3)] / [(x²+4x+3)(x+3)]
⇨ (2x²+6x-2x-6-4x²-16x-12)/ [(x²+4x+3)(x+3)]
⇨ (-2x²-12x-16)/[(x+1)(x+3)(x+3)]
⇨ (-1)(2x²+12x+16) / [(x+1)(x+3)(x+3)]
⇨ (-1)[(2x+4)(x+4)] / [(x+1)(x+3)(x+3)]
⇨ (-2)[(x+2)(x+4)] / [(x+1)(x+3)(x+3)]
Soal gak bagus. masa gak ada faktor yang saling coret. :(