acim
Int x√(x + 1) dx misal, u = x + 1 -----> x = u - 1 du = dx = int (u - 1)√u du = int (u - 1) u^(1/2) du = int u^(3/2) - u^(1/2) du = 1/(3/2 + 1) u^(3/2 + 1) - 1/(1/2 + 1)u^(1/2 + 1) + C = 2/5 u^(5/2) - 2/3 u^(3/2) + C = 2/5 (x+1)^(5/2) - 2/3 (x+1)^(3/2) + C
misal, u = x + 1 -----> x = u - 1
du = dx
= int (u - 1)√u du
= int (u - 1) u^(1/2) du
= int u^(3/2) - u^(1/2) du
= 1/(3/2 + 1) u^(3/2 + 1) - 1/(1/2 + 1)u^(1/2 + 1) + C
= 2/5 u^(5/2) - 2/3 u^(3/2) + C
= 2/5 (x+1)^(5/2) - 2/3 (x+1)^(3/2) + C