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Integral TakTentu∫ cos 2x √ (sin 2x) dx =
∫ cos 2x . (sin 2x) ¹/² dx
u = sin 2x
du = 2 cos 2x dx
cos 2x dx = 1/2 du
∫ cos 2x . (sin 2x)¹/² dx = 1/2 ∫ u¹/² du
= 1/2 (2/3) (u)³/² + c
= 1/3 u√ u + c
= 1/2 sin 2x √ (sin 2x) + c
5)
∫ (x² + 2) (x³ + 6x + 1)¹/² dx
u = x³ + 6x + 1
du = 3x² + 6 dx
du = 3(x² + 2) dx
(x² + 2) dx = 1/3 du
1/3 ∫ u¹/² du =
= 1/3 (2/3) u³/² + c
= 2/9 u√u + c
= 2/9 (x³ + 6x +1) √(x³ +6x + 1) + c