Question

Hasil dari integral (3 - 6sin^2 x) dx adalah

Answer 1

   int 3 - 6
= int 3 (1 - 2)
= int 3 ()
= int 3 cos2x
= sin 2x + c

Answer 2

Alternative :
sin^2 x = (1 - cos(2x))/2
so,
int (3 - 6sin^2 x) dx
= int ( 3 - 6(1-cos(2x))/2) dx
= int (3 - 3 + 3cos(2x)) dx
= int 3cos(2x) dx
= 3/2 sin(2x) + C