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misal : u = 1 - 2x ⇒ 2x = 1 - u ⇒ x = (1/2)(1 - u)
du/dx = - 2
dx = - (1/2) du
soal menjadi :
∫ x (1 - 2x)³ dx = ∫ (1/2) (1 - u) .u³ . (-1/2) du
= (- 1/4) ∫ u³ - u^4 dx
= (- 1/4) { 1/4 .u^4 - 1/5 .u^5 } + c
= (- 1/4) (1/20) u^4 ( 5 - 4 u) + c
= (- 1/80) (1 - 2x)^4 {5 - 4(1 - 2x) + c
= (- 1/80) (1 - 2x)^4 (5 - 4 + 8x) + c
= ( - 1/80) (1 - 2x)^4 (1 + 8x) + c
= (- 1/80) (1 + 8x) (1 - 2x)^4 + c
jawaban : b