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rumus abc
x1,2 = -b+-√b²-4.a.c
2.a
= 2+-√-2²-4.3.-8
2.3
=2+-√4+96
6
=2+-√100
6
=2+10
6
= 12/6
x1= 2
x2 = 2-10
6
=-8/6
x2=-4/3
hingga x1 dan x2 yaitu { -4/3 dan 2}
semoga membantu
* yg dikali hasilnya (3)(-8) > (-24) >> (koefisienx²)(koefisien yg tdak ada x)
* yg ditambah hasilnya (-2) >> (koefisien x)
** (-6)(4) = (-24)
** (-6) + (4) = (-2)
jdi
(3x - 6)(3x - 4) = 0
(x - 2)(3x - 4) = 0
*** x - 2 = 0
x = 2
*** 3x - 4 = 0
3x = 4
x = 4/3
Smoga mmbntu... :)