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3K + 2C = 300.000
K + 4C = 400.000 (dikali 3)
3K+2C = 300.000
3K+12C = 1.200.000
-10C = -800.000
C = Rp. 80.000
masukkan C = 80.000 ke salah satu persamaan di atas
K+4C = 400.000
K+(4x80.000) = 400.000
K +320.000 = 400.000
K = Rp. 80.000
harga sebuah kemeja = Rp. 80.000
1K + 4C = 400.000 ⇒ ×3
Pke cara eliminasi:
3K + 2C = 300.000
3K +12C =1.200.000
-10C = -900.000
C = -900.000 ÷ -10
C = 90.000
1K + (4×90.000) = 400.000
1K = 400.000- 360.000
1K = 40.000