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ax² + bx + c = 0 dengan a ≠ 0
Rumus :
x₁ + x₂ = - b/a
x₁x₂ = c/a
x₁ - x₂ = √D /a
x₁² + x₂² = (x₁ + x₂)² - 2x₁x₂
Menentukan persamaan kuadrat baru:
x² - (α + β)x + αβ = 0
Persamaan kuadrat x² - 3x + 1 = 0. Tentukan persamaan kuadrat baru yg akar-akarnya 2α dan 2β ?
Jawab:
x² - (2α + 2β)x + 4αβ = 0
x² - 2(3)x + 4(1) = 0
x² - 6x + 4 = 0