1a x= 24
1b x= 5
2a L = 336 K = 96
2b L = 830 K = 160
3a x=18 y=9√3
3b x=6 y=6√3
4a 8√2
4b 3√2
5. 27m
1a.
30² = 18² + x²
x² = 30² - 18²
x² = 900 - 324
x² = 576
x = √576
x = 24
1b.
15² = 10² + x²
x² = 15² - 10²
x² = 225 - 100
x² = 25
x = √24
x = 5
2a.
x² = 16² + 12²
x² = 256 + 144
x² = 400
x = √400
x = 20
34² = 16² + y²
y² = 34² - 16²
y² = 1.156 - 256
y² = 900
y = √900
y = 30
Luas = (a.t)/2
L = [(y+12)(16)]/2
L = [(30+12)(16)]/2
L = (42.16)/2
L = 336
Keliling = s + s + s
= 34 + x + (y+12)
= 34 + 20 + (30+12)
= 34 + 20 + 42
= 96
2b.
25² = 15² + k²
k² = 25² - 15²
k² = 625 - 225
k² = 400
k = √400
k = 20
t² = 48² + 20²
t² = 2.304 + 400
t² = 2.704
t = √2.704
t = 52
Luas = [(AB + CD) × y]/2
L = [(73 + 10) × 20] /2
L = (83×20)/2
L = 830
Keliling = AB + BC + CD + DA
K = 73 + 52 + 10 + 25
K = 160
3a.
PR : PQ = 1 : √3
9 : y = 1 : √3
y = 9.√3
y = 9√3
x² = 9² + y²
x² = 9² + 9√3²
x² = 81 + 243
x² = 324
x = √324
x = 18
3b.
AB : BC = 2 : 1
12 : x = 2 : 1
2x = 12
x = 6
12² = x² + y²
y² = 12² - x²
y² = 12² - 6²
y² = 144 - 36
y² = 108
y = √108
y = 6√3
4a.
AC² = AB² + BC²
x² = 8² + 8²
x² = 64 + 64
x² = 128
x = √128
x = 8√2
4b.
KM² = KL² + LM²
√72² = x² + x²
√72² = 2x²
√72 = 2x
6√2 = 2x
x = 3√2
5. Diilustrasikan seperti gambar berikut
RC² = RB² + BC²
29² = y² + 20²
y² = 29² - 20²
y² = 841 - 400
y² = 441
y = √441
y = 21
52² = AB² + 20²
AB² = 52² - 20²
AB² = 2.704 - 400
AB² = 2.304
AB = √2.304
AB = 48
x = AB - y
x = 48 - 21
x = 27
Jadi jarak kedua kapal tsb adalah 27m
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1a x= 24
1b x= 5
2a L = 336 K = 96
2b L = 830 K = 160
3a x=18 y=9√3
3b x=6 y=6√3
4a 8√2
4b 3√2
5. 27m
Cara Pengerjaan
1a.
30² = 18² + x²
x² = 30² - 18²
x² = 900 - 324
x² = 576
x = √576
x = 24
1b.
15² = 10² + x²
x² = 15² - 10²
x² = 225 - 100
x² = 25
x = √24
x = 5
2a.
x² = 16² + 12²
x² = 256 + 144
x² = 400
x = √400
x = 20
34² = 16² + y²
y² = 34² - 16²
y² = 1.156 - 256
y² = 900
y = √900
y = 30
Luas = (a.t)/2
L = [(y+12)(16)]/2
L = [(30+12)(16)]/2
L = (42.16)/2
L = 336
Keliling = s + s + s
= 34 + x + (y+12)
= 34 + 20 + (30+12)
= 34 + 20 + 42
= 96
2b.
25² = 15² + k²
k² = 25² - 15²
k² = 625 - 225
k² = 400
k = √400
k = 20
t² = 48² + 20²
t² = 48² + 20²
t² = 2.304 + 400
t² = 2.704
t = √2.704
t = 52
Luas = [(AB + CD) × y]/2
L = [(73 + 10) × 20] /2
L = (83×20)/2
L = 830
Keliling = AB + BC + CD + DA
K = 73 + 52 + 10 + 25
K = 160
3a.
PR : PQ = 1 : √3
9 : y = 1 : √3
y = 9.√3
y = 9√3
x² = 9² + y²
x² = 9² + 9√3²
x² = 81 + 243
x² = 324
x = √324
x = 18
3b.
AB : BC = 2 : 1
12 : x = 2 : 1
2x = 12
x = 6
12² = x² + y²
y² = 12² - x²
y² = 12² - 6²
y² = 144 - 36
y² = 108
y = √108
y = 6√3
4a.
AC² = AB² + BC²
x² = 8² + 8²
x² = 64 + 64
x² = 128
x = √128
x = 8√2
4b.
KM² = KL² + LM²
√72² = x² + x²
√72² = 2x²
√72 = 2x
6√2 = 2x
x = 3√2
5. Diilustrasikan seperti gambar berikut
RC² = RB² + BC²
29² = y² + 20²
y² = 29² - 20²
y² = 841 - 400
y² = 441
y = √441
y = 21
AC² = AB² + BC²
52² = AB² + 20²
AB² = 52² - 20²
AB² = 2.704 - 400
AB² = 2.304
AB = √2.304
AB = 48
x = AB - y
x = 48 - 21
x = 27
Jadi jarak kedua kapal tsb adalah 27m