" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Sean U y V dichos vectores.
U = (4, 5, 3) - (3, - 1, 2) = (1, 6, 1)
V = (4, 5, 3) - (- 2, 4, 6) = (6, 1, - 3)
Luego P = U x V = (1, 6, 1) x (6, 1, - 3) es el vector perpendicular.
Supongo que sabes hallar un producto vectorial.
P = (19, 3, - 37)
Verificamos que P es perpendicular a U y a V
El producto escalar debe ser nulo
P . U = (19, 3, - 37) . (1, 6, 1) = 19 + 18 - 37 = 0
P . V = (19, 3, - 37) . (6, - 1, 3) = 114 - 3 - 111 = 0
Saludos Herminio