Explicación paso a paso:
A) [tex](4x+5)^2=0[/tex]; [tex]4x+5=0;[/tex] [tex]x=-\frac{5}{4}[/tex]
B) [tex](10m^2+3)^2=0;[/tex] [tex]10m^2+3=0;[/tex] [tex]m^2=-\frac{3}{10} \\m=\sqrt{-\frac{3}{10} } \\[/tex]
m=±[tex]i\sqrt{\frac{3}{10} }[/tex]
entonces "m-x" podría ser:
1)
[tex]m-x=-i\sqrt{\frac{3}{10} } -(-\frac{5}{4} )\\m-x=-i\sqrt{\frac{3}{10} }+\frac{5}{4}\\m-x=\frac{5}{4}-i\sqrt{\frac{3}{10} }[/tex]
2)
[tex]m-x= \frac{5}{4} + i\sqrt{\frac{3}{10} }[/tex]
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Explicación paso a paso:
A) [tex](4x+5)^2=0[/tex]; [tex]4x+5=0;[/tex] [tex]x=-\frac{5}{4}[/tex]
B) [tex](10m^2+3)^2=0;[/tex] [tex]10m^2+3=0;[/tex] [tex]m^2=-\frac{3}{10} \\m=\sqrt{-\frac{3}{10} } \\[/tex]
m=±[tex]i\sqrt{\frac{3}{10} }[/tex]
entonces "m-x" podría ser:
1)
[tex]m-x=-i\sqrt{\frac{3}{10} } -(-\frac{5}{4} )\\m-x=-i\sqrt{\frac{3}{10} }+\frac{5}{4}\\m-x=\frac{5}{4}-i\sqrt{\frac{3}{10} }[/tex]
2)
[tex]m-x= \frac{5}{4} + i\sqrt{\frac{3}{10} }[/tex]