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primero encontarmos la pendiente (m)
m=y2-y1...............m=3-(-1)...........m= 3+1 ......m= 4 ............m=2
x2-x1 4-2 2 2
ahora utilizamos el modelo punto-pendiente.
y-y1=m(x-x1)
y-(-1)=2(x-2)
y+1=2x-4
y=2x-4-1
y=2x-5
la recta que pasa por (2,-1) (4,3) es y=2x-5
...........................................................
b) P(-3, 2) y Q(1, -4) x1= -3 y1=2 x2=1 y2= -4
m=y2-y1....m= -4-2 .........m= -6 ........m=- 6 ..........m= - 3
x2-x1 1-(-3) 1+3 4 2
modelo punto-pendiente.
y-y1=m(x-x1)
y-2= -3/2(x-(-3))
y-2= -3/2(x+3)
y-2= -3x - 9
2 2
y= - 3x - 9 + 2
2 2
y= - 3x - 5
2 2