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Punto P: (X , 0); Q = (3 , -2)
X1 = X; Y1 = 0; X2 = 3; Y2 = -2
d = 5: Elevo en ambos lados al cuadrado
(5)² =
25 = 13 - 6X + X²
0 = -25 + 13 - 6X + X²
0 = -12 - 6X + X²
X² - 6X - 12 = 0
Donde: a = 1; b = -6; c = -12
X1 = [6 + 9.16515]/2 = 15.16515/2 = 7.582575
X2 = [6 - 9.16515]/2 = -3.16515/2 = -1.582575
Ambas soluciones sirven entonces los puntos son
(7.582575 , 0) ó (-1.582575 , 0)
Te anexo una grafica de la situacion