Question

Hadeuh besok ulangan , bantu dong :'(
Tentukan Sisa dari (a˄3 - 4a˄2b + 3ab˄2 – b˄3) : (a-2b)

Answer 1

A- 2b = 0
a = 2b sub ke a^3 - 4 a^2b + 3 ab^2 - b^3
= (2b)^3 - 4 (2b)^2.b + 3(2b)(b^2) - b^3
= 8b^3 - 16 b^3 + 6b^3 - b^3
= (8-16+6-1)b^3
= - 3b^3