S = a O = 4a + 3c Na = b + c Br = b + c Productos: H = 2e S = d O = 4d + e Na = 2d Br = 2f H: 2 a =2e S: a = d O: 4a +3c = 4d+e Na: b + c =2d Br: b + c = 2f a=3 b=5 c=1 d=3 e=3 f=3 Ecuación ya balanceada: 3H2SO4 + 5NaBr + NaBrO3 →3Na2SO4 + 3H2O + 3Br2.
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Reactantes:
H=2a
S = a
O = 4a + 3c
Na = b + c
Br = b + c
Productos:
H = 2e
S = d
O = 4d + e
Na = 2d
Br = 2f
H: 2 a =2e
S: a = d
O: 4a +3c = 4d+e
Na: b + c =2d
Br: b + c = 2f
a=3
b=5
c=1
d=3
e=3
f=3
Ecuación ya balanceada:
3H2SO4 + 5NaBr + NaBrO3 →3Na2SO4 + 3H2O + 3Br2.