Zasady dynamiki Newtona, 2 kl. gimnazjum
Autobus o masie 2t ruszając osiąga prędkość 54km/h w 15s. Opory ruchu wynoszą 200N. Oblicz siłę działania silnika.
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Zad.6
m = 2000 kg
v = 54 km/h = 54 * 1000m / 3600s = 15m/s
t = ¼ min = 15s
F₁= 200N
F = ?
F = Fw + F₁
Fw = m*a
a = v/t
a = 15m/s / 15s = 1m/s²
Fw = 2000kg * 1m/s² = 2000N
F = 2000N + 200N = 2200N = 2,2kN