Oblicz moc samochodu rozwijajacego predkośc 108km/h przy oporach ruchu o łacznej wartosci 900 N
Wielkie dziękiii :***
P=W/t
W=F*s
P=F*(s/t)
P=F*v
108km/h=108*1000m/3600s=30m/s
P=900N*30m/s
P=27000W=27kW
dane:
v =108km/h =108 *1000m/3600s =30m/s
F = 900N = 900kg*m/s2
szukane:
P =?
P =W/t
----------
W = F *s
P =F *s/t
s/t =v
P = F * v
P = 900kg*m/s2 * 39m/s = 27 000 J/s = 27 000W
P = 27 kW
=========
Odp.Szukana moc to 27kW (kilowatów).
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=W/t
W=F*s
P=F*(s/t)
P=F*v
108km/h=108*1000m/3600s=30m/s
P=900N*30m/s
P=27000W=27kW
dane:
v =108km/h =108 *1000m/3600s =30m/s
F = 900N = 900kg*m/s2
szukane:
P =?
P =W/t
----------
W = F *s
P =F *s/t
s/t =v
P = F * v
P = 900kg*m/s2 * 39m/s = 27 000 J/s = 27 000W
P = 27 kW
=========
Odp.Szukana moc to 27kW (kilowatów).