Jaka wartosc ma sila dosrodkowa, ktora powoduje,że samochód o masie 1 t poruszajacy sie z predkoscia 90 km/h nie wypada z zakretu o promieniu 200 m?
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
dane:
m = 1 t = 1000 kg
v = 90 km/h = 90·1000m/3600s = 25 m/s
r = 200 m
szukane:
Fr = ?
Fr = mv²/r
Fr = 1000kg·(25m/s)²/200m = 3 125 kg·m/s² = 3 125 N
Fr = 3 125 N = 3,125 kN
v=90km/h=25m/s
m=1t=1000kg
r=200m
Fd=?
Fd=mv²/r
Fd=1000*25²/200
Fd=3125N
odp
sila wynosi 3125N