Question

h. me ayudan con este ejercicio paso x paso porfavor gracias​

Answer 1

Respuesta:

[tex]x=\dfrac{1}{4}[/tex]

Explicación paso a paso:

[tex]\large{\boxed{\mathsf{ Para\ la\ Ecuaci\'on }}[/tex]

[tex]\dfrac{x}{2}-\dfrac{x}{3}=\boldsymbol{ \dfrac{1}{6}(x-\dfrac{3}{2})}+x[/tex]

[tex]\boldsymbol{\dfrac{x}{2}-\dfrac{x}{3}}=\dfrac{1}{6}x+\dfrac{1}{6}.(-\dfrac{3}{2})+x[/tex]

[tex]\dfrac{\boldsymbol{3x-2x }}{6}=\dfrac{1}{6}x+\dfrac{1}{6}.(-\dfrac{3}{2})+x[/tex]

[tex]\dfrac{x}{6}=\boldsymbol{ \dfrac{1}{6}x}+\dfrac{1}{6}.(-\dfrac{3}{2})+x[/tex]

[tex]\dfrac{x}{6}= \dfrac{x}{6} +\boldsymbol{\dfrac{1}{6}.(- \dfrac{3}{2}) } +x[/tex]

[tex]\dfrac{x}{6}=\dfrac{x}{6}-\dfrac{1}{4}+x[/tex]

[tex]\dfrac{x}{6}=\dfrac{x}{6}+\boldsymbol{x}-\dfrac{1}{4}[/tex]

[tex]\dfrac{x}{6}=\boldsymbol{\dfrac{x}{6} }+\dfrac{x}{1}\boldsymbol{-\dfrac{1}{4} }[/tex]

[tex]\boldsymbol{ \dfrac{x}{6}=\dfrac{2x-3}{12}+\dfrac{x}{1}}[/tex]

[tex]2x = 14x-3[/tex]

[tex]2x - 14x=-3[/tex]

[tex]-12x=-3[/tex]

[tex]12x=3[/tex]

[tex]\boldsymbol{\Longrightarrow } x=\dfrac{1}{4}[/tex]

Espero que te haya servido mi respuesta.  

Atte..

[tex]\boxed{ \boxed{Emily\ Nicolette}}[/tex]