Z jaką siłą porusza sie auto o masie 100kg jeżeli w czasie 2s zwiększyło prędkość 36km/h do 108km/h. Jaką drogę pokona w tym czasie?
basetla
Dane: m = 100 kg t = 2 s v1 = 36 km/h = 36 *1000m/3600s = 10 m/s v2 = 108 km/h = 108 *1000m/3600s = 30 m/s szukane: F = ? s = ?
Siła Z II zasady dynamiki Newtona: F = m * a ale a = dv/t dv = v2 - v1 = 30m/s - 10m/s = 20 m/s a = dv/t = 20m/s/2s = 10 m/s2 = 10 N/kg F = m * a F = 100kg * 10N/kg F = 1000 N = 1 kN
Droga s = vot + at^2/2 s = 10m/s * 2s + 10m/s2 *(2s)^2/2 =20m + 20m s = 40 m
m = 100 kg
t = 2 s
v1 = 36 km/h = 36 *1000m/3600s = 10 m/s
v2 = 108 km/h = 108 *1000m/3600s = 30 m/s
szukane:
F = ?
s = ?
Siła
Z II zasady dynamiki Newtona:
F = m * a
ale a = dv/t
dv = v2 - v1 = 30m/s - 10m/s = 20 m/s
a = dv/t = 20m/s/2s = 10 m/s2 = 10 N/kg
F = m * a
F = 100kg * 10N/kg
F = 1000 N = 1 kN
Droga
s = vot + at^2/2
s = 10m/s * 2s + 10m/s2 *(2s)^2/2 =20m + 20m
s = 40 m