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s=
u=45kmh-1 (12,5ms-1)
v=15kmh-1 (4,167ms-1)
a=
t=5s
Sabemos que:
a=(v-u)/t
a=(4,167-12,5)/5
a=-1,66ms-²
Buscamos la distancia:
s=(v+u/2)t
s=(12,5+4,167/2)5
s=41,667m