Posługując się informacjami na dole, oblicz ile czasu potrzeba :
-koń na przebycie 9 km
-sprinter na przebycie 300 metrów
galopujący koń | m/s 15 | | km/h 54 |
sprinter | |m/s 15 | | km/h 36 |
Plis o pomoc ;] ;* bd wdzięczna
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dane:
s(k) = 9 km = 9000 m
v1(k) = 15 m/s
v2(k) = 54 km/h = 54 *1000m/3600s =15 m/s
v1(k) = v2(k)
s(s) = 300 m = 0,3 km
v1(s) = 15 m/s
v2(s) = 36 km/h
szukane:
t1(k) = t2(k) = ?
t1(s) = ?
t2(s) = ?
t = s/v
t1(k) = t2(k) = 9000m/15m/s = 600s
t1(k) = t2(k) = 10 min
===================
t1(s) = s(s)/v1(s) = 300m/15m/s = 20s
t1(s) = 20s
==========
t2(s) = s(s)/v1(s) = 0,3km/36km/h = 1/120 h = 30s
t2(s) = 30s
==========
Dane z indeksem (k) dotyczą konia; z indeksem (s) dotyczą sprintera.
koń:
sprinter:
300m : 15m = 20s