Question

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Answer 1

Verified answer

Penjelasan dengan langkah-langkah:

A(0,-2)

B(-4,0)

mAB = mCD

Then gradient of AB

m = (yB-yA)/(xB-xA)

m = (0-(-2))/(-4-0)

m = 2/-4

m = -½

Gradient of BC

m = -1 ÷ -½

m = -1 × -2/1

m = 2

Then C coordinates if we know xC = 0

y = 2(xC-xB)

y = 2(0+4)

y = 8

Then coordinates C = ( 0 , 8 )

Then line equation CD

y - yC = mCD(x-xC)

y - 8 = -½(x-0)

y - 8 = -½x

y = -½x + 8 ( A ) ✓