Jawaban:
C. 2y + 3x + 1 = 0
Penjelasan dengan langkah-langkah:
4. m = has a gradient perpendicular to line n
coordinates n ( 0 , 2 ) & ( -3 , 0 )
then
[tex]\rm m_n[/tex] = (0-2)/-3-0 = 2/3
.
gradient definitiont ( perpendicular )
[tex]\boxed{\rm m_1\times m_2=-1}[/tex]
then [tex]\rm m_m \:is[/tex]
[tex]\begin{aligned}\rm m_m&=\rm-1\div\frac{2}{3}\\&=\rm \frac{-3}{2}\end{aligned}[/tex]
then the equation of the straight line m is
y - y1 = m(x-x1)
y -(-2) = -3/2(x-1)
y + 2 = -3/2x + 3/2
y + 3/2x + 2 -3/2 = 0
y + 3/2x + 1/2 = 0 .....( Times 2)
2y + 3x + 1 = 0
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Verified answer
Jawaban:
C. 2y + 3x + 1 = 0
Penjelasan dengan langkah-langkah:
4. m = has a gradient perpendicular to line n
coordinates n ( 0 , 2 ) & ( -3 , 0 )
then
[tex]\rm m_n[/tex] = (0-2)/-3-0 = 2/3
.
.
gradient definitiont ( perpendicular )
[tex]\boxed{\rm m_1\times m_2=-1}[/tex]
then [tex]\rm m_m \:is[/tex]
[tex]\begin{aligned}\rm m_m&=\rm-1\div\frac{2}{3}\\&=\rm \frac{-3}{2}\end{aligned}[/tex]
.
then the equation of the straight line m is
y - y1 = m(x-x1)
y -(-2) = -3/2(x-1)
y + 2 = -3/2x + 3/2
y + 3/2x + 2 -3/2 = 0
y + 3/2x + 1/2 = 0 .....( Times 2)
2y + 3x + 1 = 0