Question

Guys no 6 dan no8 bantu dong.
kalau ga bisa no6 ,no8 aja bantu ..please yah lg urgent :)

Answer 1

6).


8). xy = x^y ------>y = x^y/x = x^(y - 1)
dan
x/y = x^5y, maka
x/x^(y-1) = x^5y
x^(2-y)  = x^5y
2 - y =5y
2 = 6y
y = 1/3
substitusi :
xy = x^y
x(1/3) = x^1/3
x = 3 * x^1/3
kedua ruas pangkat 3 kan,
x^3 = 27x
x^2 = 27
yg ditanya nilai x² + 3y,
maka x² + 3y = 27 + 3(1/3) = 27 + 1 = 28