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Q = 1,6 kkal
c = 1 kal/g°C = 0,001 kkal/kg°C
T₂ = 100°C
- Ditanya : T₁
- Jawab :
Q = m × c × ΔT
1,6 = m × c × ( T₂ - T₁ )
1,6 = 0,2 × 0,001 × ( 100 - T₁ )
1,6 = 0,0002 × ( 100 - T₁ )
100 - T₁ = 1,6 : 0,0002
100 - T₁ = 8.000
-T₁ = 8.000 - 100
-T₁ = 7.900
T₁ = -7.900 kkal
Begitu ya !!