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memotong di sumbu x jika y = 0
x =0 --> y=f(0) = 2.0²-6.0 - 8 = -8
(0,-8)
y= 0 --> y=f(x) = 0 = 2x²-6x-8
0 = 2 (x²-3x-4)
x²-3x-4 = 0
(x-4)(x+1) = 0
x-4 = 0 dan x+1=0
x = 4 dan x = -1
(4,0) dan (-1,0)
titik potong sb x (4,0) dan (-1,0)
titik potong sb y (0,-8)